Chaotic Glass by Mike Aurelius

Safety for the glassworker, and random thoughts and opinions on the state of the glassworking world

Air temperature and altitude corrections for ventilation systems

Posted by mikeaurelius on January 30, 2009

Altitude and air temperature make a substantial difference in the performance of any ventilation system. The calcuations I have provided here: http://mikeaurelius.wordpress.com/2007/12/25/ventilation-basics-part-two/ are based on sea level and 70 degrees F.

In the calculations, the only variable that needs modifying is VP, Velocity Pressure. The standard calculation is (V/4005) squared.

When applying temperature and altitude corrections, use the following equation: VP = ((V/1096.7) squared) times ‘density of the air in pounds per cubic foot’.

The following table gives standard Density of air in pounds per cubic foot.

Air Temp

Altitude in Feet above Sea Level

0

1000

2000

3000

4000

5000

6000

7000

8000

9000

10000

-25

.092 .088 .085 .082 .079 .076 .073 .071 .068 .066 .063

0

.086 .083 .080 .077 .075 .072 .069 .067 .064 .062 .059

25

.082 .079 .076 .074 .071 .068 .066 .063 .061 .059 .057

50

.078 .075 .073 .070 .067 .065 .062 .060 .058 .056 .054

70

.075 .072 .070 .067 .065 .062 .060 .058 .056 .054 .052

100

.071 .068 .066 .064 .061 .059 .057 .055 .053 .051 .049

125

.068 .066 .063 .061 .059 .057 .055 .053 .051 .049 .047

As an example, let’s go back to example one on the above referenced link and apply both an altitude and temperature correction to the design.

Example:

CFM = 1300

Altitude = 5,000 feet above sea level

Temperature = 100 degrees (summer average)

Duct size = 6″ round (or .196 square feet) Use the area of a circle formula (Pi times radius squared) divided by 144.

Total run = 6 feet.

Number of Bends: 0

Loss Factor: 0.11 (from Table 1)

Solve for Velocity: 1300 / .196 = 6632 Feet per Minute

Solve for VP: (6632/1096.7) squared times .059 (from table above) = 2.15

Solve for SP: 2.15 times 6 times .11 = 1.42 inches of pressure

 As you can see from the original calculation in example 1 where the calculated static pressure was 1.80 inches, increasing altitude and/or temperature decreases the static pressure in the system. This is due to the fact that at higher altitudes, air is less dense than at sea level.

However, note the temperatures. If your average temperature is below 70 F, your static pressure is going to increase, because cold air is more dense than warm air. This means that your ventilation system is going to be slightly more inefficient in the winter than it will be in the summer.

2 Responses to “Air temperature and altitude corrections for ventilation systems”

  1. Linda said

    Thank you very much, Mike. This is most helpful to those of us working at high elevations and colder climates!

    Linda

  2. You are very welcome!

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